2.1 Find the Acceleration of a Ball Rolling Down an Inclined Angle Iron by Drawing a Graph between 2S and t2
Observations and Calculations
| No | Distance covered by ball S (m) |
Time taken by ball | t2 (s2) |
2S (m) |
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| t1 s |
t2 s |
t=(t1+t2)/2 s |
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| 1 | 50 | 0.9 | 1.1 | 1 | 1 | 100 |
| 2 | 100 | 1.3 | 1.5 | 1.4 | 1.96 | 200 |
| 3 | 150 | 1.8 | 1.6 | 1.7 | 2.89 | 300 |
| 4 | 200 | 1.9 | 2.1 | 2 | 4.00 | 400 |
| 5 | 250 | 2.6 | 2.2 | 2.4 | 5.76 | 500 |
| 6 | 300 | 2.6 | 2.8 | 2.7 | 7.29 | 600 |
2.2 To Find the Value of ” g ” by Free Fall Method
Observation and Calculation
| No | Initial Position of bob h1(cm) |
Position of mark h2(cm) |
Height h=h2-h1 (cm) |
| 1 | 97 | 17 | 80 |
| 2 | 97 | 17 | 80 |
| 3 | 97 | 17 | 80 |
time
t1=16.03 sec
t2=16.00 sec
t3=15.75 sec
Mean time t0 = (t1+t1+t1)/3
t0 = 15.927 sec
Time period of the bob = T = t0/10
T = 1.592 sec
Time for free fall = t = T/4
t = 0.398 sec
Value of g = 2h/t2
g = 1066.6 cms-2
Result
The value free fall acceleration ” g ” is 10.666 ms-2.